Answers from page 13.

Here are the answers for the "physics of a wave on a string question". Hope you all had a good weekend.

Mr V

a) (1 mark)

For each complete wave cycle of the wave, a particle on the string moves a total distance of 4A where A is the amplitude of the wave.

The total distance moved by the particle is 4(2.0 mm) = 8.0 mm.

b) (1 mark)

The frequency of the wave is 2500 Hz

c) (1 mark)

The period of motion is the inverse of the frequency: 4.0 x 10^-4 s

d) (1 mark)

For each second, or one period of motion of the wave, the vertical distance travelled by the particle is 8.0 mm or 0.0080 m. To travel a distance of 1.0 km, the number of cycles of the wave (or periods of motion) is

number of cycles = 1.25 x 10⁵ cycles

e) (1 mark)

The total time required is

t = (1.25 x 10⁵ cycles)(4.0 x 10^-4 s/cycle) = 5.0 x 10¹ s